Comment Re:Read the Text (Score 1) 88
If those two floating wires are unconnected to an EMF, the two capacitors will still have the same voltage across them, due to whatever charge/energy is stored in them.
There are two problems with this. First what happens if the components are resistors? Is this some new rule you have invented that only applies to capacitors while resistors in the exact same arrangement will not be connected in parallel just because they cannot generate their own EMF? Next this argument seems to distinguish whether something is in parallel or series based on the addition of two unconnected wires. If I remove those two, unconnected wires are you trying to tell me that this will convert the connection from parallel to series? Really? If A and B are connected to some external circuit with a current flowing through it then you have a parallel connection. If that circuit is removed then the circuit becomes the capacitor loop and that's a simple series loop - two unconnected wires with no current in them make no difference.
And in fact it'll be behaving like one capacitor with the sum of capacitance in that regard.
No, it only behaves that way relative to an external circuit applying a pd between A and B. If A and B are disconnected then one capacitor can be driving a current around that, now series, loop and charging the other and good luck describing that circuit with a single capacitor.
Now replace the resistor with a switch. Are those capacitors still in parallel?
Yes, when the switch is closed those capacitors are connected in parallel to the battery. When the switch is open the battery is no longer part of a circuit and the capacitors are connected in series with each other because now any current will have to flow around the capacitor loop. Simply adding superfluous, unconnected components to a simple series loop does not convert it into a parallel connection.