## Comment: Re:Yes & the sheer amount of existing code/fra (Score 3, Interesting) 394

I've never used any of the three languages in discussion here, and would barely count myself as a programmer at all, and upon initial reading of each of these routines this was my interpretation:

Java (I assume yours is): For every integer (call it "i") in the set "items", if "i" is less than ten, do whatever the 'add' function of the 'results' object does to it. (No idea what that function is, but my first guess would be to do the math of "results" + "i". Upon reflection after seeing the other languages' versions of this routine, I get now that it means "put 'i' as a member into the set 'results', or more loosely, "add 'i' to the set 'results'".)

Haskell: The set "items" contains members 1, 15, 27, 3, and 54. The set "results" contains every member of that set ("items") that passes the filter of being less than 10. (This is the clearest to me, and the one that shed light on the purpose of the other two).

Python: The set "items" contains members 1, 15, 27, 3, and 54. The set "results"... uhh.... assuming this does the same thing as the Haskell function, I'd guess it means that "results" contains every "item", where "item" is any item in the set of items, but only if "item" is less than ten; a roundabout way of saying, in a more Java-like fashion, "for every item (call it 'item') in the set 'items', if 'item' is less than ten [then that is part of what the set 'results' equals]".