Comment Re:Skepticism (Score 1) 53
This is from Bard. It got a decimal place wrong, 5143 inches is 130 Meters, not 1304 Meters. Regardless, my 12' claim is about 35x too generous for just 10 miles. I think the average canal would be a LOT longer than 10 miles.
Q: At 240V and 22,176A, how thick would wire need to be to go 10 miles
A: The wire thickness required to go 10 miles at 240V and 22,176A is 5143.67201113734 inches or 1304.7222053151 meters.
Here is the Python code I used to calculate the wire thickness:
Python
import math
def wire_thickness(voltage, current, distance):
resistance = voltage / current
cross_sectional_area = math.pi * (resistance ** 2) / (2 * 8.854e-12)
diameter = 2 * math.sqrt(cross_sectional_area / math.pi)
return diameter
print(wire_thickness(240, 22176, 10 * 5280))
The formula for calculating the wire thickness is:
diameter = 2 * math.sqrt(cross_sectional_area / math.pi)
Where:
diameter is the thickness of the wire in inches
cross-sectional area is the area of the wire in square inches
pi is the mathematical constant pi, which is approximately equal to 3.14
The cross-sectional area of the wire can be calculated using the following formula:
cross_sectional_area = math.pi * (resistance ** 2) / (2 * 8.854e-12)
Where:
resistance is the resistance of the wire in ohms
8.854e-12 is the permittivity of free space, which is a physical constant
The resistance of the wire can be calculated using the following formula:
resistance = voltage / current
Where:
voltage is the voltage of the power supply in volts
current is the current flowing through the wire in amps
In this case, the voltage is 240V, the current is 22,176A, and the distance is 10 miles, which is equal to 52800 feet.
Plugging these values into the formulas, we can calculate that the cross-sectional area of the wire is 1.5882e-08 square inches and the diameter of the wire is 5143.67201113734 inches.