That depends how high you go when you say "more massive". For example, the black hole at the center of our galaxy is 4 million solar masses, and ones thought to be as heavy as 1 billion solar masses have been spotted I believe. Lets do some basic maths of proportions. The Schwarzchild radius of a blackhole is proportional to its mass. Not the something-root of its mass, but to its actual mass. That's unexpected, and it's why the other guy was almost right (but not about micro black holes). Newtonian gravity is M G / r^2 (where G is the gravitational constant G = 6.67E-11 m^3/(kg s^2)). So it will vary with mass, and inversely with squared distance. Distance at the event horizon, we just established, will vary with mass. So force at the event horizon varies with the inverse of the mass. So a 1E6 solar mass black hole would have 1E-6 as much gravity at its event horizon. So instead of about about 1.5E13, it would be 1.5E7. That's still a lot of gravity! However, remember that we are also 1E6 times as far away. The difference that 1.5M makes is then 1E-6 as great. While you might initially expect this to be 1E-12 because of it being squared, you'd be wrong if you did so. You'll have r^2 - (r+1.5)^2 = r^2 - (r^2 + 3r + 1.5^2), or proportional to r, not to r^2. So all told, the tidal forces should vary inversely with the square of the mass of the black hole. Thus, I would expect the gradient to be 1E-12 as great, or basically 2 thousandths of a gravity over 1.5 meters. More than the tidal forces of standing on Earth, but not something that will shred you. The other considerations vis-a-vis dying in a horrifying (but thankfully brief) manner at that distance are another matter entirely. But as pointed out it's a pretty rough guess to be using Newtonian gravity while standing, as it were, directly on a singularity. And about that word: A black hole can have two different sorts of singularities. A singularity means a point at which an equation is undefined. (In the equation 1 / (1-X), X=1 is a singularity). The event horizon is a singularity in equations for relativity. At this point, length and time are 0, and mass is undefined. The second singularity is what everybody always thinks of. That is a point mass, or a point with 0 volume and finite mass. Density = mass/volume. Finite/0 is undefined, so a point mass is a singularity of a different sort. However, I should note that a point mass is only required for small black holes. As the radius varies with the mass, and the volume of a sphere varies with the cube of the radius, the density of a black hole is proportional to the inverse square of its mass. When you get to the millions or billions of solar mass black holes, the density is very low and no point mass is necessary.