When Apple released their iPad with retina display I read that the additional pixels require more electronics in the display which block some of the light. This in turn means that a stronger backlight is needed to have the same light output compared to a lower resolution display. For LCD it was an important factor at that time. For OLED, this might not make that much of a difference unless some of the connections would be on top of the pixels or due to a minimum border size per pixel.

Not always

Are you sure you don't mean sweep for every possible IP? In case of a private network, that would be 16 million addresses (1.6 * 10^7) which is a lot less than 2.81 * 10^14. Unless it filters MAC addresses somehow, exhausting the entire range would require going through 2.81 * 10^14 addresses. If that were possible using just 1 bit of traffic per address, it'd still take 2.81 * 10^14 / 10^7 (10Mbps) = 2.81 * 10^7 seconds which is just over 325 days.

That number is large.

You're supposed to put all your devices behind the "Whitebox". Using your solution would give them skewed results, according to their terms:

The Whitebox should be placed in between your existing router and your networked computers. Any devices that connected via ethernet cable to your existing router should instead connect to the Whitebox. This ensures that the SamKnows device is always aware of the network being used and will never run tests at a time when you require your full bandwidth to be available. (Whitebox faq)

The problem of factoring a large number is hard when it's a semiprime where both factors are very large numbers around the same magnitude as the square root of the semiprime. In this case 191605050401140404051920181528 can be factored into 2^3 * 3 * 23 * 222647 * 694079 * 8335727 * 269462689 which is easy to factor as the one but largest factor is only ~= 8 million. A naive program that just divides by 2 and all odd numbers up to 8335727 can give you the answer in less than a minute on a moderate computer nowadays. After finding the 8335727 factor you know that you will not have any more factors in 269462689 since sqrt(269462689) ~= 16415 which is the largest divisor you'd have to try to factor it.

Don't click the 'Get certificate' button. Once you click 'Add exception' and the pop-up is shown, Firefox is already retrieving the certificate. When it has retrieved the certificate, the 'Permanently store this exception' box is checked. If you click, 'Get certificate', the process starts over again. So what happens is that you uncheck the 'Permanently' checkbox and the 'Get certificate' process will re-check it again just before your click on the 'Confirm' button is processed. Indeed, very annoying.

63 servers * 48 disk of 1 TB = 3024 TB. According to the announcement on the archive.org 3 Petabytes would be right.

Then again, check the news section after logging on to Metalink:

So it does appear that it won't take too long before you'll be unable to use Metalink without flash.

If you can't get the receiver on the WinTV card to work, you can also build a small receiver yourself. It's easy to build, and easy to set up with lirc: http://www.lirc.org/receivers.html