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Comment Re: Solar fricken roadways all over again (Score 1) 120

The total blackbody radiation emitted by the cylinder in space is approximately 124.32 kilowatts
The total power radiated is determined using the Stefan-Boltzmann Law:(P = \sigma \cdot A \cdot T^4\)Stefan-Boltzmann Constant (\(\sigma \)): \(5.6704 \times 10^{-8} \text{ W/m}^2\text{K}^4\)Temperature (\(T\)): \(20^\circ\text{C} = 293.15\text{ K}\)Radius (\(r\)): \(3.5\text{ m}\) (half of the 7m width)Length (\(L\)): \(10\text{ m}\)Surface Area ScenariosTotal Surface Area (With End Caps): \(296.88\text{ m}^2\)Formula: \(2\pi rL + 2\pi r^2\)Total Radiation: 124.32 kW

Comment Re: Solar fricken roadways all over again (Score 1) 120

A good thermos is also silvered to prevent radiation losses.
I am having trouble explaining to you how heat can be lost into a vacuum insulator. Perhaps think of it the other way. How hot does the Sun feel? That heat has got to you through many miles of vacuum insulator.
A satellite at a much cooler temp also shines , but less

Comment Re: Solar fricken roadways all over again (Score 1) 120

Sorry, I didn't answer your question about 212F.
The exterior of the example 7mx10m satellite is not 212F it would very quickly cool down to an equilibrium temp nearer room temp. This is because hotter objects emit more infra red.
It has to be large because it needs the large surface area to shine the heat out and also to contain the cosmic radiation shielding

Comment Re: Solar fricken roadways all over again (Score 1) 120

Space telescopes have to be kept cold because they are trying to see in effect heat. A I follows
Space telescopes that observe the universe in the infrared spectrumâ"such as the James Webb Space Telescope (JWST) and the former Spitzer Space Telescopeâ"must be kept at near-absolute zero temperatures.The Problem with Self-Radiation: Infrared light is essentially heat radiation. Every warm object, including the telescope itself, glows in infrared light.

Comment Re: Solar fricken roadways all over again (Score 1) 120

No it doesn't.

Imagine a datacenter launched by starship. It is cylindrical, 7m across and 10m long. At one end solar panels open like a flower and provide 100kW of electricity.

Inside it is a rack of nvdia's powerful GPGPU using all that 100kW and turning it to hot air in the cylindrical datacenter. How much cooling do you think you need?

The answer is none. The surface of the cylinder dissipates more than 100kW just through blackbody radiation.

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Heavier than air flying machines are impossible. -- Lord Kelvin, President, Royal Society, c. 1895

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