Comment Physics for dummys (Score 1) 268
P=workdone/time
5 calories/gram of sugar (being nice here)
1 calorie=4.184 joules (not kilo joules. If you yankees worked in metric like everyone else in the world we wouldn't have this problem)
therefore 50g of sugar has 5*50*4.184=1046 joules
once again joules not kilo joules.
P=workdone/time
therefore assumming 100% efficiency (good luck) the maximum power obtainable over eight hours is
1046 joules/(8*60*60 seconds)
=36mWatts. Oh my god this is great we can run a 36mWatt light bulb for 8 hours with 50g of sugar.
5 calories/gram of sugar (being nice here)
1 calorie=4.184 joules (not kilo joules. If you yankees worked in metric like everyone else in the world we wouldn't have this problem)
therefore 50g of sugar has 5*50*4.184=1046 joules
once again joules not kilo joules.
P=workdone/time
therefore assumming 100% efficiency (good luck) the maximum power obtainable over eight hours is
1046 joules/(8*60*60 seconds)
=36mWatts. Oh my god this is great we can run a 36mWatt light bulb for 8 hours with 50g of sugar.
