Comment Did nobody do the math at FCC? (Score 2) 79
The solar constant is roughly 1361 Watts per square meter. The mirror is 60x60 feet or A_mirror = 335 mÂ. The target area is about 3 miles wide or 5.8 km (assuming a square) or A_target = 5.8 mn mÂ. The mirror will be tilted at 45 degrees give or take, so we need to take the cosine of 45 degrees = 0.7071 into account. The earth's atmosphere has a transparency of estimated 80 percent in clear weather conditions.
Taken together, the energy flux on the ground will be solar constant x A_mirror / A_target x 0.7071 x 0.8 which is approximately 0.45 watts per square meter.
What in the world does anybody think it is good for - except burning investor money?