To make this a bit more rigorous:

\infty = 0^{-1} [A20]
0^{-1] = 1*(0^{-1}) [A14]
1*(0^{-1}) = 1/0 [A17]
1/0 = 1/(-1*0) [T77]

From this point, you cannot apply commutativity of multiplication, of all things, to jump to your next step. You'll have to find some other way to break the axioms.

-fs

0.0001% != 0.0001, 0.001% != 0.001, and 0.1% != 0.1. So multiply your result by (1%)^3 = 10^-6.