Comment Re:Why Ruby? (Score 1) 199
Have you tried it?
>>> a = { 1 : 2 }
>>> b = { ( 'foo' , 'bar' ) : 4 }
>>> c = dict( a , **b )
>>> a , b , c
({1: 2}, {('foo', 'bar'): 4}, {1: 2, ('foo', 'bar'): 4})
