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Comment OFFTOPIC: MATHS PROBLEM (Score 0) 119

This topic has to do with crypto which has to do with maths so here I go:-

You have 5 distinct CS books, 3 distinct math books and 2 distinct art books.

Q: How many ARRANGEMENTS if art books are NOT together?

My thinking:

Total arrangements 10!

Arrangements with art books together: 9!2!

Hence arrangements not together == 10! - 9!2!

== 2903040

Is this right? I know its damn easy but my brain isn't working now.
Maybe I should just write a bash script to enumerate all the possibilities. I bet someone could do it in a one liner. Too sleepy though.

All flames to /dev/null.

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