Comment Re:Sorry that isn't covered in High School Physics (Score 0) 243
Resistance contributes quite a bit to heat.
Most examples I have seen here so far have correctly stated Power = Volts * Amps, but incorrectly stated that 'Power' is being dissipated.
Here's an example:
Say you were to place a 4ohm resistor in series with a load, the load would get 1/4 the power it normally gets. In order to provide the load with the proper amount of power, the voltage will need to be increased to bring the watts back to the proper value, thus putting more power into the circuit.
No resistor:
(Power = Volts * Amps) 24Watts = 12VDC * 2ADC
With Resistor:
96Watts = 48VDC * 2ADC
Therefore, more resistance = more heat, WITH A LOAD
Most examples I have seen here so far have correctly stated Power = Volts * Amps, but incorrectly stated that 'Power' is being dissipated.
Here's an example:
Say you were to place a 4ohm resistor in series with a load, the load would get 1/4 the power it normally gets. In order to provide the load with the proper amount of power, the voltage will need to be increased to bring the watts back to the proper value, thus putting more power into the circuit.
No resistor:
(Power = Volts * Amps) 24Watts = 12VDC * 2ADC
With Resistor:
96Watts = 48VDC * 2ADC
Therefore, more resistance = more heat, WITH A LOAD
