Comment Re:So what will happen in practice? (Score 1) 687
haha
Comment better idea? (Score 1) 354
urls posted to twitter should automatically be converted to a shortened url supported by twitter themselves:
tweet: "check this out http://foo.com/bar/lots/of/crap.html?a=1&b=2&c=3..."
should appears as: "check this out http://twitter.com/$user/x"
(where x is an unique id)
there would be a limit on the number of urls encoded per hour
after a 24 hours or so, the urls would automatically expand in your tweet history.
additionally, you could list all the shortened urls you are provided and convert them to long urls manually.
tweet: "check this out http://foo.com/bar/lots/of/crap.html?a=1&b=2&c=3..."
should appears as: "check this out http://twitter.com/$user/x"
(where x is an unique id)
there would be a limit on the number of urls encoded per hour
after a 24 hours or so, the urls would automatically expand in your tweet history.
additionally, you could list all the shortened urls you are provided and convert them to long urls manually.
NASA Releases Columbia Crew Survival Report 223
Migraineman writes "NASA has released a 400-page Columbia Crew Survival Investigation Report [16MB PDF.] If you're interested in a detailed examination and timeline of the events leading to the destruction of Columbia, this is well worth the time. The report includes a number of recommendations to increase survivability of future missions." Reader bezking points out CNN's story on the report, which says that problems with the astronauts' restraint systems were the ultimate cause of death for the seven astronauts on board.
Comment A few lines of Mathematica (Score 1) 311
ClearAll[solve, jump];
$Jumps = {{-2, 1}, {-1, 2}, {1, 2}, {2, 1}, {2, -1}, {1, -2}, {-1, -2}, {-2, -1}};
solve[n_] := (ClearAll[board]; Catch[jump[1, 1, 1, n]]; Array[board, {n, n}]);
jump[x_, y_, z_, n_] /; 1 <= x <= n && 1 <= y <= n && ! ValueQ[board[x, y]] := (
board[x, y] = z;
If[z == n^2, Throw[1]];
jump[x + #1, y + #2, z + 1, n] & @@@ $Jumps;
board[x, y] =.;
);
Block[{$RecursionLimit = Infinity}, solve[5] // MatrixForm]
$Jumps = {{-2, 1}, {-1, 2}, {1, 2}, {2, 1}, {2, -1}, {1, -2}, {-1, -2}, {-2, -1}};
solve[n_]
jump[x_, y_, z_, n_]
board[x, y] = z;
If[z == n^2, Throw[1]];
jump[x + #1, y + #2, z + 1, n] & @@@ $Jumps;
board[x, y] =.;
);
Block[{$RecursionLimit = Infinity}, solve[5]
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