Comment Re:Lots of Negativity Around This Story... (Score 1) 426
Has anyone done the maths on this (I haven't RTF)..
Assuming this ONLY works on gravity the most force obtained by system is:
F = m x a (assume car is 1 ton and acceleration is 9.8)
F = 9800 N (say 10 kN)
Work produced by system from car travelling over hump:
W = 2 x F x D (assume D = 10 cm, which is a big hump note 2 x force as run over hump twice front and back wheels)
W = 2000 J
The power output for that one hour is:
P = W / t
P = 55.5 W
Assuming we only need 8 hours of light, so we have can say the power supplied is 160 W (Approx 0.2 KW not 10 KW as reported).
Someone can check my reasoning, but 10 KW as stated seems quite high for using gravity of the car.
Assuming this ONLY works on gravity the most force obtained by system is:
F = m x a (assume car is 1 ton and acceleration is 9.8)
F = 9800 N (say 10 kN)
Work produced by system from car travelling over hump:
W = 2 x F x D (assume D = 10 cm, which is a big hump note 2 x force as run over hump twice front and back wheels)
W = 2000 J
The power output for that one hour is:
P = W / t
P = 55.5 W
Assuming we only need 8 hours of light, so we have can say the power supplied is 160 W (Approx 0.2 KW not 10 KW as reported).
Someone can check my reasoning, but 10 KW as stated seems quite high for using gravity of the car.
