This command finds all directories with .*.cmd files (like all the .o.cmd files generating when building the kernel) and set the svn ignore command on them

svn status | grep "\.cmd" | cut -b8- | cut -d. -f1 | sort | uniq | xargs svn propset svn:ignore '.*.cmd'

Ok, I reallt needed a bash command that could list the index of every occurance of a pattern in a file. I found this one-liner before:

perl -0777 -ne 'print index $_, "\x5d\x00\x00\x80\x00\x00"' afile.bin

This locates the first LZMA header in a file, but I need to find ALL headers, not just the first... Ok, I'm no perl specialist, but I came up with this:

#!/usr/bin/perl
use strict;
use warnings;

my $count = @ARGV;
if ( $count < 2 ) {
print "bff - Binary Find in Files. Finds all occurances of a string in a file\nusage: bff <string> <filename>\n";
exit();
}

open FILE, $ARGV[1] or die $!;
my $char = eval '"'.$ARGV[0].'"';
my $offset = 0;
my $result = index(<FILE>, $char);

while ($result != -1) {
$offset += $result;
print "Found at $offset\n";

$offset += 1;
seek FILE, $offset, 0;
$result = index(<FILE>, $char);
}

This allows me to write

bff "\x5d\x00\x00\x80\x00\x00" afile.bin

and lists all occurances of the header in the file.

As always, this is a personal reference page, but use it if you like it...

VAR=hello in all examples

String length: ${#VAR}
ex:
echo ${#VAR} #yields '5'

Substring: ${#VAR:[chars to remove from start]:[chars to return]}
Last parameter can be ignored if you want to the end ("${VAR:2}")
ex:
echo ${VAR:1:3} #yields 'ell'

Remove last character: ${VAR%?}
ex:
echo ${VAR%?} #yields 'hell'

Return last character: ${VAR:${#VAR}-1}
Bit messy, best I could find though
ex:
echo ${VAR:${#VAR}-1} #yields 'o'

To be continued...

This is a follow up on the previous post about easter day, the function getEasterDate is required...

This calculates the number of work days between two dates, using Swedish holidays.

This consists of two functions, one that calculates if a given day is a holiday (isHoliday()) and one that simply loops through the range of days given and checks if any is a holyday (numberOfWorkDays())

If anyone wants to convert this to another country or optimize this one, please tell me about it! I'd love to see it...

Create Function isHoliday(@date as datetime)
returns bit
as begin
    if DATEPART(dw, @date) in (1,7)
        or (DAY(@date)=1 and MONTH(@date) in (1,5)) --Jan 1, May 1
        or (DAY(@date)=6 and MONTH(@date)=6) --6 july, national day
        or (MONTH(@date)=12 and DAY(@date) in (25,26)) --xmas
        return 1
    declare @easter as datetime set @easter = dbo.getEasterDate(YEAR(@date))
    if DATEDIFF(day, @easter, @date) in (-2, 1, 39) --easter + ascention
        return 1
    return 0
end

go

Create function numberOfWorkDays( @fromDate as datetime, @toDate as datetime)
returns int
as begin
    declare @day as datetime
    declare @endday as datetime
    declare @dayCount int

    set @day = @fromdate
    set @endday = @toDate
    set @dayCount = 1

    if @endday @day begin
        declare @tempday datetime set @tempday=@day
        set @day=@endday
        set @endday = @tempday
    end

    while @day @endday begin
        if dbo.isHoliday(@day)=0
                set @dayCount = @dayCount + 1

        set @day = dateadd(day, 1, @day)
    end

    return @dayCount
end

A SQL function to calculate the easter date on any given year:

create function getEasterDate( @yr int )
returns datetime
As Begin

        declare @g int, @c int, @x int, @z int, @d int, @e int, @n int

        set @g = @yr % 19 + 1
        set @c = @yr / 100 + 1
        set @x = (3 * @c) / 4 - 12
        set @z = (8 * @c + 5) / 25 - 5
        set @d = (5 * @yr) / 4 - @x - 10
        set @e = (11 * @g + 20 + @z - @x) % 30

        if (@e = 24) or ((@e = 25) and (@g > 11)) set @e = @e + 1

        set @n = 44 - @e
        if (@n 31 begin
                set @g = 4
                set @n = @n-31
        end

        return cast( cast(@yr as varchar) + '-' + cast(@g as varchar) + '-' + cast(@n as varchar) as datetime)
End