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Comment Re:Time is an angle (Score 1) 235

Longitude can be expressed using gradians quite well (with 400 grads per full circle). Then it works out to one centigrad of arc on the equator equaling one kilometer.

In fact, during the aborted trial of decimal time right after the french revolution there were almanacs published with exactly that system - grads, decimal time and kilometers. And guess what, the same formulas for spherical trigonometry work out exactly the same as they do with the usual system of degrees, H/M/S and nautical miles.

Comment Re:Pilot's seat (Score 1) 549

OK, after being accused of picking nits, let me just explain that as a private pilot I love flying, but only in one context - operating an aircraft. For me at least other options of the poll where you are a passive spectator of the voyage are "being flown".

I don't think that the other proposed interpretations of my post really work since piloting is flying, whereas driving a boat or submarine cannot be interpreted in the other sense - being driven in the boat, or worse swimming.

As per Merriam Webster the verb "fly" can be used as a transitive verb to represent operating an aircraft. Interestingly, "I usually fly Economy class" does not parse according to M-W.

Comment Re:Checks and transfers (Score 1) 796

Luxembourg has a hugely convenient institution of pursuits office. Same with Switzerland, but I don't know about the other countries. It comes down to the principle of trust between parties, with the state carrying a big stick if that trust is breached. In both countries I was able to spend huge sums of money with deferred payments (like 10-30 days after the delivery of the product or the service) based on the trust by the seller that I will make the payment (or that my life and credit would be completely ruined to kingdom come if I did not and that they would still get the money).

Comment Re:Well... I could. (Score 1) 612

Sure does work for negative degrees. Or are you implying that anti-logarithm is defined for complex values whereas the logarithm is not defined for negative values?

Where I come from ln(-1) = i*pi, since e^(i*pi) = -1.

We could argue that it would work for 0 as well if we accept that ln(0) = -inf, and that e^-inf = 0.

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