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Comment Re:Oh, one other thing... (Score 1) 226

My hand is hold a string. String is glued to surface or rock. I begin spinning it. The string is exerting a centripetal force on the rock via the molecules on the inward surface of the rock. These molecules are pulling inward on the next layer of molecules. The first layer of molecules are feeling a force outward (CENTRIFUGUAL FORCE) that equals the force they are pulling the other molecules inward with. This outward force that the first layer of molecules feels is exactly equal to the force required to impart the necessary inward accelleration to all of the outward mass for it to follow a circular path. The inward force on the inward layer of molecules is greater than the outward pull of the remainder of the pass so the inward layer of molecules feel a net inward force. So, yes, in all cases the NET force is only inward, but, the individual components are not only inward.

Comment Re:BZZT! WRONG! (Score 0, Troll) 226

OK, so where is the force coming from to overcome air resistance to keep imparting a tangential component to the velocity? The rock has an instantaneous velocity tangent to the circle. That means it will experience an opposing force in the opposite direction also tangent to the circle that will slow the velocity causing it to lose momentum and stop. Now, what is overcoming this air resistance? Well, I'm pulling the string slightly (ever so) ahead of a line perfectly perpendicular from the objects instantaneous velocity and the center of the circle about which I am causing it to revolve. So, no, I am not wrong. You are over-simplifying and ignoring the obvious. YOU ARE WRONG! You call me wrong and fail to point out why. You are an arrogant asshole that gives scientists and mathematicians a bad name. You are the reason why people tend not to believe proper scientists, engineers, and mathematicians. You are so certain you are right because you are so EDUMACATED that you fail to see the obvious flaws in your reasoning.

Comment Re:BZZT! WRONG! (Score 1) 226

The rock is exerting a reaction force on your hand.

Yes, that is what I said

But this on no way implies that there is an outward force on the rock

Errm, when did I say there was?

Getting back to the rubber band in TFA, what does it exert centrifugal force force on?

What does that have to do with anything? You said, "Centrifugal Forces do not exist", not "Centrifugal Forces are not applicable to the current problem."

Centrifugal force, if it were real, would be exerted on the rock, not the string or your hand.

What an odd definitiaon of "Real"?!?!

You seem to the think the centrifugal force is exerted on your hand.

Yeah, it is! And to point out your earlier quote...

The rock is exerting a reaction force on your hand.

Yep, just what I said. So, we're in agreement that the rock exerts a centrifugal force on my hand, but, then you question me when I think that. Hmmm, it seems to me that you are forgetting the basics and getting wrapped up in the wrong details and the wrong way of looking at it

In your other post you finish with:

I’ve taken both college-level physics and calculus and I know that if you integrate a constant force parallel to the string – centripetal force – AND NO OTHER FORCES, then you take a specific initial velocity at a certain tangential velocity perpendicular to the force – you get the velocity vector of a circularly orbiting object traveling at a constant speed but with constantly changing direction. NO OTHER FORCE EXISTS IN THE SYSTEM, AND THE CALCULUS SUPPORTS THIS.

Well, let's have a look at this. Force Parallel to String - Check. Constant Velocity of Rock - Check. Changing Velocity - Check. Then you say, "NO OTHER FORCE EXISTS IN THE SYSTEM". WHAT? What are you considering "THE SYSTEM"? All you talked about was the forces acting on the rock, nothing else. "THE SYSTEM" is my hand, the string, and the rock. Now, what are all the FORCES? What's that tug I feel on my hand that I have to exert energy to overcome? Oh, that's the CENTRIFUGAL FORCE my hand is experiencing.

Comment Re:BZZT! WRONG! (Score 2) 226

That force is directed outward radially. It is a centripetal^h^h^h^h^h^h^h^h^h^h^hCENTRIFUGAL force. Yes, I have calculated this using Calculus as well. Yes, I know there is not CENTRIFUGAL FORCE acting on the ROCK, but, there is a CENTRIPETAL^h^h^h^h^h^h^h^h^h^h^hCENTRIFUGAL FORCE acting on my hand and the string that IS a manifestation of the intertia of the rock.

Woops! In my haste I had a couple of typos.

Comment Re:BZZT! WRONG! (Score 1) 226

Here is where your analysis is incomplete and WRONG! What gives the rock it's momentum along the tangent? The String. Which is NOT pulling straight towards the center of the overall circular motion. In order for me to make the thing start swinging I need a big pull initially NOT in the direction of the center that I'm going to revolve the rock around. Then, also, I need to continue to impart a slight force along the tangent in order to overcome air resistance. Therefore, I am not consistently pulling directly towards the center of the overall motion. Then you say, the rock is not pulling back on my hand with an equal force to the centripetal force that it is experiencing. You say, what I feel is the inertia of the rock. Yeah, that inertia is imparting a force onto the string and my hand. That force is directed outward radially. It is a centripetal force. Yes, I have calculated this using Calculus as well. Yes, I know there is not CENTRIFUGAL FORCE acting on the ROCK, but, there is a CENTRIPETAL FORCE acting on my hand and the string that IS a manifestation of the intertia of the rock. I think that perhaps you understand less than you think you do.

Comment Oh, one other thing... (Score 1) 226

Every Molecule in the Rock and String, other than the single Molecule that is farthest from the center of the circle, simultaneously feels a Centripetal, and Centrifugal Force. That is because that while each molecule is experiencing a force pulling towards the center of the circle, that same molecule is also pulling on the next molecule in the chain, which is pulling back, therefore the first molecule experiences a "Centrifugal Force" equal to the "Centripetal Force" it pulls with to the next molecule in the chain. So, one can say everything in the system other than the outermost molecule is experiencing "Centrifugal Force". Now, is it so incorrect to talk about "Centrifugal Force"? Me thinks not. It is simpler to think of the system in terms of "Centripetal Force" and "Radial Force", but, you can also think of it in terms of "Centrifugal Force" quite well.

Comment BZZT! WRONG! (Score 2, Interesting) 226

You, like many of the others above, FAIL! There is Centrifugal Force. If I spin a rock at the end of a rope, the rock experiences a "Centripetal Force" which is a force pulling towards the center of a circle, where my hand is, that is perpendicular to it instantaneous velocity. Note, it is not only experiencing a "Centripetal Force", otherwise it would just accelerate along the radius toward the center. It is in fact also experiencing a force along the tangent (i.e. the diretion of instantaneous velocity) of the same circle. But, here is where it gets interesting. It is actually experiencing neither of those. It is in fact experiencing a force that is at an angle slightly between the direction of the tangent to the circle and along the radius. We can break that actual force (the real direction I'm actually pulling on the string) into the component along the radius and the component along the tangent, but, there really isn't two separate forces acting, just one. So, what you are calling "Centripetal Force" doesn't actually exist either. It's just a a convenient name for the component of the force pulling inward along the radius. Now, according to Newton's Laws, for every force (action) there is an equal an opposite force (re-action). So, if there is a corresponding force pulling inward on the rock (the "Centripetal Force") then there is also a force pulling outward along the radius (the "Centrifugal Force"). In fact, the Rock is pulling on my hand with such an equal and opposite force. So, my hand (and the string) is experiencing "Centrifugal Force". So, "Centrifugal Force DO EXIST!" You FAIL! Go back and re-read your Physics text-book and try again!

Thank You for Playing!

Comment And here... (Score 1) 617

...is one of those lazy, good-for-nothing teachers we were talking about that collect there 45k/year salary, work less than 9 months out of the year, and still fail to deliver a useful product. Why is that? What are YOU doing wrong? Perhaps all your bullshit "Teaching Methods" are for shit. Maybe, just maybe, you are completely full of shit. Maybe, just maybe, you are an ineffective twit. Perhaps if 80% of the teachers who obviously don't know the subject they are teaching beyond a rudimentary level, actually knew something, and could convey it to another human being with something resembling a compellling and interesting discussion, then there wouldn't be so many failing students? Hmmm, wonder what that would be like?

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