Comment Contradiction!? (Score 1) 217
The summary mentions that Facebook is forming a PAC, and that it already IS a Palo Alto Company??
The summary mentions that Facebook is forming a PAC, and that it already IS a Palo Alto Company??
Do you think there will really be separate buildings like that on the moon, rather than indoor interconnected complexes?
Would save a lot of decompression chambers, etc. Or why not make a tube system for transportation of goods (and internet packets) while you are at it!
Seems like MS will not let go of their old ideas
http://www.zdnet.com/news/microsoft-flushes-out-iloo-gag/129298
Mac OS X: http://www.apple.com/downloads/macosx/games/role_strategy/foxminesweeper.html
Debian GNU/Linux: http://packages.debian.org/lenny/xbomb
FreeBSD: ftp://ftp.internat.freebsd.org/pub/FreeBSD/ports/i386/packages-8-current/games/xdemineur-2.1.1_1.tbz
Windows Vista: http://windows.microsoft.com/en-US/windows-vista/Learn-about-Windows-games
HA!
As somebody else pointed out, it only holds for x>4.
The proof is simple.
1) If x> 4 and x-1 is a prime number, then x-1 is odd. Therefore x is even - i.e. 2 is a prime factor of x.
2) for any three successive integers x-1,x,x+1, exactly one of the three numbers is divisible by 3 (basically if x-1 mod 3 is 1, then x mod 3 is 2 and x+1 mod 3 is 0, etc). Back to our problem - since x-1 and x+1 are assumed to be primes, the number divisible by 3 is in fact x.
Thus, x is divisible by both 2 and 3, i.e. it is divisible by 6.
"The medium is the massage." -- Crazy Nigel