Follow Slashdot blog updates by subscribing to our blog RSS feed

 



Forgot your password?
typodupeerror
For the out-of-band Slashdot experience (mostly headlines), follow us on Twitter, or Facebook. ×

Comment: Re:forgive me for possibly being redundant, but .. (Score 1) 263 263

True. But power out does not mean squat! Just because I have a million watt transmitter does not mean, based on this "7.08 Mbps per MHz per watt" or whatever it is, that all the receivers are going to be receiving data at 7.08 x 10^6 bps.

The key words in Shannon's Theorem are "signal to noise ratio".

The farther out you go from the transmitter, the worse the s/n ratio is going to be. Likewise a crappy antenna. Or crappy obstructions. Or crappy weather. Or a damn bird flying right between the transmitter and receiver. It doesn't matter how much power is being used - if any of the crappy things above happen, the s/n ratio is going to go down.

Instead of saying "7.08 Mbps per watt per MHz" or whatever it was, they need to instead say something like "7.08 Mbps per MHz with a S/N ratio of whatever-it-was."

Comment: Re:The "Service" (Score 2, Informative) 630 630

But to demand I remove a file off my personal hard drive because it is in violation of their Acceptable Use?
Eh? They're not demanding that you remove it from your hard drive. They're demanding that you "remove the allegedly infringing works from the Service". In other words stop providing access to them over the Comcast network.

"Everyone is entitled to an *informed* opinion." -- Harlan Ellison

Working...