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Comment: Re: Numerology (Score 1) 182

Nope. It an experimental measurement that DOES depend on the interpretation chosen. If (otherwise QM-compatible) local realistic theories (a.k.a. local hidden-variables) are true, abs(delta)=2. If standard QM (without hidden variables) is true, delta=2*sqr(2), and the Bell inequality is violated (as was shown to be the case). What differs, in a nutshell, is the ontology pressuposed by the theory in each interpretation -- once a component associated with "strictly philosophical" discussions, nowadays proved to have measurable experimental consequences. Thus the term "experimental metaphysics" coined by philosophers of physics Abner Shimony and Michael Redhead. The outermost formalism is in both cases the same, but it is a narrow view to think that formalism is all there is to theory. It is but an element of it. Theories include, in a substantive way, e.g. ontological commitments and methodological assumptions as well (to speak nothing of values, etc).

Comment: Re: Numerology (Score 1) 182

"All arguments about interpretations of quantum mechanics are philosophical in nature. None of them change the actual calculations done to make quantitative predictions. They can help give you ideas for what to try next..." Well, (1) What about the Bell inequality? That's an old-school quantitative prediction, as far as I know. (2) Philosophical / interpretive arguments don't just "give ideas for what to try next". They can foster rational intelligibility of Nature, which does not seem like a minor bonus to me.

Comment: Re:Computable? Simulatable? (Score 1) 199

Well, Bolotin's reasoning seems fascinating at first sight, but it's worth recalling that there is a VERY strong realist assumption hidden there, namely, that the universe constantly "solves" Schrödinger's equation in order to work. Now that's two subtly (but crucially) different things to say that that: (1) certain properties of our world are well *described* by Schr's Eqn., and that: (2) certain features of the world *depend* on computational properties of Schr's Eqn. What one can say for sure is that Schr's Eqn. is our representation. To say anything stronger than this would require an independent defense of scientific realism (certainly not a trivial task).

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