Comment Re:Billions and billions... (Score 3, Funny) 356
Let's run the math:
(Using classical mechanics, Google Calculator, and some rounding)
40 days, 60 million km to mars at closest approach.
Spend half the time accelerating, half the time decelerating.
For acceleration:
x = x0 + v0t + (at^2)/2
2 * 30 million km / (20 days) ^ 2 = 2e-2m/s^2
Let's use a Space Shuttle, 2,029,203 kg
The force of the engine is
F = ma = ((2 029 203 kg) * 2 * (30 million km)) / ((20 days)^2) = 40 774.5587 newtons
Work along a straight line is Force time distance
W = Fd = (40 774.5587 newtons) * 30 million kilometers = 1.22323676 × 10^15 joules
Power is work over time
P = W/t = 1.22323676 × ((10^15) joules)) / (20 days) = 0.707891644 gigawatts
Of course, we need to do this twice:
Ptotal = 2P = 2 * 0.707891644 gigawatts = 1.41578329 gigawatts
Which is surprisingly close to the power needed to propel a DeLorean through time...
Note that this is only the power needed to get the ship to Mars and then stop it; I have no idea the efficiency of their engine, life support, etc, but hey, the math works close enough for me.
I'm a little weak on my power generation math- anyone who knows something about solar panels and PV arrays want to take a shot at the power requirements?