Comment Re:This is just faulty math (Score 1) 1260
This works in any simple base using the same concept of decimal representation.
In base x, consider the number zero followed by n digits of (x-1) after the decimal point, e.g. 0.FF...F with n Fs for hexadecimal. One minus this number gives the difference 1/x^n. In the limit n goes to infinity, this difference goes to zero for real numbers. And with the real numbers, zero difference means they are the same number.