"Reader SpuriousLogic notes that it's also getting easier to keep an eye on modern penguins, since Google has extended Street View to Antarctica." A penguin waved at me! How polite.

I made an application on Android and i checked Objective-C recently for a project.The target app is required to be written for Android and iOS. I was checking about applications' publication on the two platforms' stores and i stumbled upon the fees that are required for developer's registration. Android : 25$ iOS: 99$.(I admit i did not expect these fees.I am student and the project is an open source one for clearly educational purposes.I got disappointed a little.) Don't forget that owning a Mac is supposed to be a prerequisite for iOS development, since Apple does not support Windows (Although i found an IDE called Titanium Developer, that i am going to use).

One is open source and the other is enough closed. However,I think approaching both platforms is the way to go.The more platforms you support ,the wider your potential customer base will be. Android = Java , iOS = Objective-C. Both have C as a base. I think you will be just fine.

reaches 40C+ in major cities like Athens.

http://www.nypost.com/p/news/national/sexy_russian_spy_anna_chapman_2Zmmc1rSqu2H71x3v7BibM?photo_num=5 One of the spies :P

I remember reading here on ./ that it got abandoned by Intel.

to be released

we use it on the networks class. nice one.

*starts packing for South Korea*

Pac-Man follows your mouse click.

It is big.

i wish i could mod you up. rly.

If you want to get rid of something, first destroy it then delete it. Otherwise, you just have evidence sitting on your disk, because whatever you delete, just has its flag changed. So it remains there , till it gets overwritten. People who would look for the file will not just use windows' search. i bet many are going to burn their HDs now.

the definition of 1337.

for(int i=1;i<=10;System.out.println(i++)); sorry for double post,but my lower than symbol got omitted by the filter.used html this time.

for(int i=1;i=10;System.out.println(i++));