This isn't a quantum effect. The reason IR detectors measure DIFFERENCES, not absolute radiation, is because electrical heating power = (e * s) * (Ta^4 - Tb^4). If that weren't true, there would be no way to detect this difference
You didn't bother to read my reference on pyrometers, did you? Because if you read it, and understood it, and were honest, you'd know that is complete bullshit. That's not the "difference" they measure.
And that's the only reason I respond to you: to show others your bullshit. Funny how you don't seem to bother to read the TEXTBOOKS on how these things actually work, and instead just toss in your own theories. And... that's how you came up with the WRONG answer, which doesn't even check out using your own equations.
Once again, Jane insists electrical heating power = (e * s) * (Ta^4). Once again, Jane's ridiculous equation doesn't just say there is no net "radiative power in" from cooler to hotter. Jane's wrongly saying the source absorbs no radiative power at all.
NO. That is NOT what I claimed, and that is not what I am claiming. That isn't even misunderstanding, it's just a lie. You HAVE TO understand this by now. You could not NOT understand it, unless you are 100% clueless about what the term NET means.
I do not claim "no" radiation is absorbed. To repeat once again: no NET power from radiation is absorbed. Those are 2 completely different claims. You keep saying I claim the former, when I've actually only claimed the latter. And by now, there can be no remaining misunderstanding about that. You are simply lying. Again.
That's odd. Just yesterday Jane had no argument with Prof. Brown. Now Jane claims that Prof. Brown is spreading "garbage" that contradicts just about every argument behind the whole idea of AGW. But Jane certainly isn't arguing with Prof. Brown or Dr. Shore or even me. Perish the thought.
No, I am not arguing with them right now, as I made clear. I was arguing with YOU about Spencer's experiment. And you lost the argument.
When A is warmer than B, (Ta^4 - Tb^4) yields a positive number. Which means all NET radiative energy transfer goes from A to B. That is clearly indicated by the minus sign, and is further dictated by the Second Law of Thermodynamics. There is no NET energy going from B to A. Only when B is hotter than A does any NET energy transfer in the other direction.
A high-schooler can easily understand this. It's simple subtraction.
Further, by the same equation the temperature (T) of warmer A does not depend on the cooler B. And as the Stefan-Boltzmann temperature-power relation (e*s)*T^4 clearly implies, the power output of A also does not depend on B.
Power output of A at a given temperature Ta is independent of B. Changing the temperature of B (as long as it remains cooler) does not affect the power output of A. This is exactly where you have been getting it wrong, by trying to use a heat transfer equation rather than a power output equation.
This is textbook stuff, and you're getting it wrong. Period. I don't give the slightest damn whether your precious professors agree or disagree. My argument was with YOU.
I haven't used moderator points in over a year. But the fact that Jane is so convinced I am that he's cussing and screaming in ALL CAPS is emblematic of Jane's reasoning problems, just like when Jane was absolutely convinced that I'm a six-headed hydra.
It fit the pattern I saw in the past. It's possible that it was someone else. Just not very likely.